13 S18 máquinas trabajaron 6 h/d durante 5 días,
¿cuántos días tardarán 10 máquinas para realizar el
mismo trabajo si funcionan durante 8 h/d?



Answer :

Answer:

12 days

Step-by-step explanation:

Let m be number of machines, R be rate of hour /day that the machines work and D be number of days.

It is inferred that m is proportional to R and inversely proportional to D

[tex] \: m = \frac{kR }{ D } [/tex]

k = mD / R, when. m = 18, D = 5 and R = 6

k = (18 × 5) / 6

k = 3 × 5

k = 15

Therefore,

[tex] \: m = \frac{15R }{ D } [/tex]

is the equation connecting the three parameters together.

D = ? when m = 10 and R = 8

[tex] \:D = \frac{15R }{ m} [/tex]

= (15 × 8) / 10

= (3 × 8) / 2

= 3 × 4

= 12.

Hence,

It will take 12 days for 10 machine a to do same work.