Answer :
The value of a car decreasing at a constant rate of 5% per year can be described by an exponential decay function. Here is a step-by-step explanation detailing how this works:
1. Identify the Initial Value and Rate of Decrease:
- Let's denote the initial value of the car as [tex]\( V_0 \)[/tex]. Suppose the initial value of the car is [tex]$10,000. - The rate of decrease is 5%, which can be written as a decimal: 0.05. 2. Exponential Decay Formula: - The formula for exponential decay is: \[ V(t) = V_0 \times (1 - r)^t \] where: - \( V(t) \) is the value of the car at time \( t \) (in years), - \( V_0 \) is the initial value of the car, - \( r \) is the rate of decrease (0.05 for 5%), - \( t \) is the number of years. 3. Calculate the Value After Each Year: - After 1 Year: \[ V(1) = 10000 \times (1 - 0.05)^1 = 10000 \times 0.95 = 9500 \text{ dollars} \] - After 2 Years: \[ V(2) = 10000 \times (1 - 0.05)^2 = 10000 \times 0.95^2 = 10000 \times 0.9025 = 9025 \text{ dollars} \] - After 3 Years: \[ V(3) = 10000 \times (1 - 0.05)^3 = 10000 \times 0.95^3 = 10000 \times 0.857375 = 8573.75 \text{ dollars} \] Therefore, the values of the car after 1, 2, and 3 years of ownership are $[/tex]9500, [tex]$9025, and $[/tex]8573.75, respectively.
In conclusion, the type of function that best describes the value of the car based on the number of years it is owned is an exponential decay function.
1. Identify the Initial Value and Rate of Decrease:
- Let's denote the initial value of the car as [tex]\( V_0 \)[/tex]. Suppose the initial value of the car is [tex]$10,000. - The rate of decrease is 5%, which can be written as a decimal: 0.05. 2. Exponential Decay Formula: - The formula for exponential decay is: \[ V(t) = V_0 \times (1 - r)^t \] where: - \( V(t) \) is the value of the car at time \( t \) (in years), - \( V_0 \) is the initial value of the car, - \( r \) is the rate of decrease (0.05 for 5%), - \( t \) is the number of years. 3. Calculate the Value After Each Year: - After 1 Year: \[ V(1) = 10000 \times (1 - 0.05)^1 = 10000 \times 0.95 = 9500 \text{ dollars} \] - After 2 Years: \[ V(2) = 10000 \times (1 - 0.05)^2 = 10000 \times 0.95^2 = 10000 \times 0.9025 = 9025 \text{ dollars} \] - After 3 Years: \[ V(3) = 10000 \times (1 - 0.05)^3 = 10000 \times 0.95^3 = 10000 \times 0.857375 = 8573.75 \text{ dollars} \] Therefore, the values of the car after 1, 2, and 3 years of ownership are $[/tex]9500, [tex]$9025, and $[/tex]8573.75, respectively.
In conclusion, the type of function that best describes the value of the car based on the number of years it is owned is an exponential decay function.