beth is 2 years older than jimmy, and in 3 years the sum of their ages will be twice as much as the sum of their ages 3 years ago. Find their present ages.



Answer :

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Jimmy is 8 years old and Beth is 10 years old.

Jimmy is 8 years old and Beth is 10 years old.Let's denote Jimmy's current age as \( J \) and Beth's current age as \( B \).

According to the given information:

1. Beth is 2 years older than Jimmy: \( B = J + 2 \)

2. In 3 years, the sum of their ages will be twice as much as the sum of their ages 3 years ago:

\( (J + 3) + (B + 3) = 2 \times [(J - 3) + (B - 3)] \)

Simplifying this equation gives:

\( J + B + 6 = 2 \times (J + B - 6) \)

\( J + B + 6 = 2J + 2B - 12 \)

\( J + B = 18 \)

Now, substituting the value of \( B \) from the first equation into this equation:

\( J + (J + 2) = 18 \)

\( 2J + 2 = 18 \)

\( 2J = 16 \)

\( J = 8 \)

So, Jimmy is 8 years old, and Beth is \( 8 + 2 = 10 \) years old.

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