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Given secant of theta is equal to the square root of 6 over 3 comma what is cos θ?

one half
square root of 14 over 7
square root of 14 over 2
2



Answer :

Answer: sqrt(6)/2

Step-by-step explanation: Sec(theta) = 1 over cos(theta)

sqrt(6)/3 = 1/cos(theta)

We find the reciprocal of sqrt(6)/3  

that would be 3/sqrt(6)      this simplifies to sqrt(6)/2

The correct answer is sqrt(6)/2

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