Certainly! Let's solve the problem step-by-step.
First, we need to understand what the notation [tex]\(4!\)[/tex] and [tex]\(3!\)[/tex] means. The symbol [tex]\(n!\)[/tex], called "n factorial," represents the product of all positive integers from 1 to [tex]\(n\)[/tex].
So,
[tex]\[ 4! = 4 \times 3 \times 2 \times 1 \][/tex]
Calculating this, we get:
[tex]\[ 4! = 4 \times 3 \times 2 \times 1 = 24 \][/tex]
Next, we calculate [tex]\(3!\)[/tex]:
[tex]\[ 3! = 3 \times 2 \times 1 \][/tex]
Calculating this, we get:
[tex]\[ 3! = 3 \times 2 \times 1 = 6 \][/tex]
Now, we need to evaluate the expression [tex]\(4! \times 3!\)[/tex]:
[tex]\[ 4! \cdot 3! = 24 \times 6 \][/tex]
Multiplying these two results:
[tex]\[ 24 \times 6 = 144 \][/tex]
Therefore, the value of the expression [tex]\(4! \cdot 3!\)[/tex] is [tex]\(144\)[/tex].
So the correct answer is:
[tex]\[ 144 \][/tex]
