Answer :
To determine the correct inequality that can be used to solve for how many souvenirs Omar can buy, let's break down the question into manageable parts.
1. Total Balance: Omar has a gift card valued at \[tex]$40.00. 2. Cost for Himself: Omar wants to buy a bracelet for \$[/tex]13.50.
3. Cost per Souvenir: Each souvenir costs \$3.25.
We need to find an inequality that represents the total cost being less than or equal to the balance on the gift card.
Let's denote:
- [tex]\( x \)[/tex] as the number of souvenirs Omar wants to buy.
Then the total cost for the bracelet and the souvenirs can be expressed as:
[tex]\[ \text{Total Cost} = \text{Cost of Bracelet} + \text{Cost per Souvenir} \times \text{Number of Souvenirs} \][/tex]
Substituting the given values:
[tex]\[ \text{Total Cost} = 13.50 + 3.25x \][/tex]
Since the total cost must be within the limits of the gift card, the inequality that represents this condition is:
[tex]\[ 13.50 + 3.25x \leq 40.00 \][/tex]
This simplifies to:
[tex]\[ 3.25x + 13.50 \leq 40 \][/tex]
Therefore, the correct choice is:
A. [tex]\(3.25x + 13.50 \leq 40\)[/tex]
1. Total Balance: Omar has a gift card valued at \[tex]$40.00. 2. Cost for Himself: Omar wants to buy a bracelet for \$[/tex]13.50.
3. Cost per Souvenir: Each souvenir costs \$3.25.
We need to find an inequality that represents the total cost being less than or equal to the balance on the gift card.
Let's denote:
- [tex]\( x \)[/tex] as the number of souvenirs Omar wants to buy.
Then the total cost for the bracelet and the souvenirs can be expressed as:
[tex]\[ \text{Total Cost} = \text{Cost of Bracelet} + \text{Cost per Souvenir} \times \text{Number of Souvenirs} \][/tex]
Substituting the given values:
[tex]\[ \text{Total Cost} = 13.50 + 3.25x \][/tex]
Since the total cost must be within the limits of the gift card, the inequality that represents this condition is:
[tex]\[ 13.50 + 3.25x \leq 40.00 \][/tex]
This simplifies to:
[tex]\[ 3.25x + 13.50 \leq 40 \][/tex]
Therefore, the correct choice is:
A. [tex]\(3.25x + 13.50 \leq 40\)[/tex]