Which chemical symbols will complete the equation for this single displacement reaction?

[tex]\[ 2 \, \text{NaBr} + \text{Cl}_2 \rightarrow \square + \square_2 \][/tex]

A. Na
B. Br
C. Cl



Answer :

To determine which chemical symbols complete the equation for the given single displacement reaction, let's consider the reactivity of the elements involved.

In the reaction:

[tex]\[ 2 \text{NaBr} + \text{Cl}_2 \rightarrow \square \+\square_2 \][/tex]

Sodium bromide (NaBr) reacts with chlorine gas (Cl_2). This type of reaction is known as a single displacement reaction, where a more reactive element displaces a less reactive element from its compound.

1. Identify the more reactive element:
In the halogen group, chlorine is more reactive than bromine. Therefore, chlorine can displace bromine in sodium bromide (NaBr).

2. Determine the products:
When chlorine (Cl_2) displaces bromine (Br) in sodium bromide (NaBr), sodium combines with chlorine to form sodium chloride (NaCl), and bromine is released as bromine gas (Br_2).

So, the products of the reaction are:
- Sodium chloride (NaCl)
- Bromine gas (Br_2)

Therefore, the complete balanced chemical equation is:

[tex]\[ 2 \text{NaBr} + \text{Cl}_2 \rightarrow 2 \text{NaCl} + \text{Br}_2 \][/tex]

The chemical symbols that complete the equation are:

[tex]\[ \boxed{\text{NaCl}} \text{ and } \boxed{\text{Br}_2} \][/tex]

Thus, the completed equation becomes:

[tex]\[ 2 \text{NaBr} + \text{Cl}_2 \rightarrow 2 \text{NaCl} + \text{Br}_2 \][/tex]