To determine the percentage of hybrid results from a cross between two heterozygous parents (Tt and Tt), we can use a Punnett square.
### Step-by-Step Solution:
1. Set up the Punnett square:
- Each parent contributes one allele to the offspring.
- One parent has the alleles T and t, and the other parent also has the alleles T and t.
2. Fill in the Punnett square:
- The top of the Punnett square represents one parent's alleles.
- The side of the Punnett square represents the other parent's alleles.
- Combine these alleles inside the square.
[tex]\[
\begin{array}{c|c|c}
& T & t \\
\hline
T & TT & Tt \\
\hline
t & Tt & tt \\
\end{array}
\][/tex]
3. Analyze the outcomes from the Punnett square:
- The possible genotypes of the offspring are TT, Tt, Tt, and tt.
- There are 4 outcomes in total.
- Hybrid offspring are those with the genotype Tt.
4. Count the hybrid outcomes:
- Tt appears 2 out of the 4 total outcomes.
5. Calculate the percentage:
- Use the formula for percentage: [tex]\(\text{percentage} = \left(\frac{\text{number of hybrid outcomes}}{\text{total outcomes}}\right) \times 100\)[/tex]
- Substitute the numbers into the formula: [tex]\(\left(\frac{2}{4}\right) \times 100 = 50\%\)[/tex]
### Final Answer:
c. [tex]\( \frac{2}{4} = 50\% \)[/tex]
So, 50% of the results from a cross between Tt & Tt would be hybrid.
