Certainly! Let's solve this stoichiometry problem step-by-step.
We start with the balanced chemical equation:
[tex]\[
ZnCl_2 + 2 NaClO_4 \rightarrow Zn(ClO_4)_2 + 2 NaCl
\][/tex]
a. The question asks us to determine how many moles of [tex]\( NaCl \)[/tex] would be produced if we start with 5 moles of [tex]\( ZnCl_2 \)[/tex].
### Step 1: Understanding the Molar Ratio
From the balanced chemical equation, we see the molar ratio between [tex]\( ZnCl_2 \)[/tex] and [tex]\( NaCl \)[/tex]:
- 1 mole of [tex]\( ZnCl_2 \)[/tex] produces 2 moles of [tex]\( NaCl \)[/tex].
### Step 2: Setting Up the Calculation
Since the molar ratio of [tex]\( ZnCl_2 \)[/tex] to [tex]\( NaCl \)[/tex] is 1:2, we can use this ratio to find out how many moles of [tex]\( NaCl \)[/tex] are produced from 5 moles of [tex]\( ZnCl_2 \)[/tex].
### Step 3: Performing the Calculation
Starting with 5 moles of [tex]\( ZnCl_2 \)[/tex]:
[tex]\[
\text{Moles of } NaCl = 5 \text{ moles of } ZnCl_2 \times 2 \text{ (moles of } NaCl \text{ per mole of } ZnCl_2)
\][/tex]
[tex]\[
\text{Moles of } NaCl = 5 \times 2 = 10
\][/tex]
### Conclusion
Therefore, if you start with 5 moles of [tex]\( ZnCl_2 \)[/tex], you will produce 10 moles of [tex]\( NaCl \)[/tex].
