Select the correct answer.

Two points located on [tex]\(\overleftrightarrow{JK}\)[/tex] are [tex]\(J(1, -4)\)[/tex] and [tex]\(K(-2, 8)\)[/tex]. What is the slope of [tex]\(\overleftrightarrow{JK}\)[/tex]?

A. -4
B. -2
C. [tex]\(-\frac{1}{4}\)[/tex]
D. [tex]\(\frac{1}{4}\)[/tex]
E. 4



Answer :

To determine the slope of the line containing the points [tex]\( J(1, -4) \)[/tex] and [tex]\( K(-2, 8) \)[/tex], we will use the slope formula:

[tex]\[ m = \frac{y_2 - y_1}{x_2 - x_1} \][/tex]

where [tex]\((x_1, y_1)\)[/tex] and [tex]\((x_2, y_2)\)[/tex] are the coordinates of the two points. Here, let:
- [tex]\( J(1, -4) \)[/tex] correspond to [tex]\((x_1, y_1) = (1, -4) \)[/tex]
- [tex]\( K(-2, 8) \)[/tex] correspond to [tex]\((x_2, y_2) = (-2, 8) \)[/tex]

Plugging the values into the slope formula, we get:

[tex]\[ m = \frac{8 - (-4)}{-2 - 1} \][/tex]

Simplify inside the parentheses:

[tex]\[ m = \frac{8 + 4}{-2 - 1} \][/tex]
[tex]\[ m = \frac{12}{-3} \][/tex]

Now, divide [tex]\( 12 \)[/tex] by [tex]\(-3\)[/tex]:

[tex]\[ m = -4 \][/tex]

Thus, the slope of the line containing points [tex]\( J \)[/tex] and [tex]\( K \)[/tex] is

[tex]\[ \boxed{-4} \][/tex]

Therefore, the correct answer is A. -4.