Let's examine the given reactions step by step to determine whether they will form products or not, based on the activity series of halogens:
### Reaction 1: [tex]\( CuI_2 + Br_2 \rightarrow \)[/tex]
According to the activity series [tex]\( F > Cl > Br > I \)[/tex], bromine (Br) is more reactive than iodine (I). However, for a reaction to occur, bromine would need to replace iodine in the compound. Since bromine is already less reactive than iodine, it cannot displace iodine from copper(II) iodide. Thus, no reaction will occur.
Conclusion: No reaction.
### Reaction 2: [tex]\( Cl_2 + AlF_3 \rightarrow \)[/tex]
Chlorine (Cl) is less reactive than fluorine (F) in the activity series. For a reaction to take place, chlorine would need to replace fluorine in the compound aluminum fluoride (AlF_3). Since chlorine is less reactive than fluorine, it cannot displace fluorine from the compound. Thus, no reaction will occur.
Conclusion: No reaction.
### Reaction 3: [tex]\( Br_2 + NaCl \rightarrow \)[/tex]
Chlorine (Cl) is more reactive than bromine (Br). In this case, for a reaction to occur, bromine would need to replace chlorine in sodium chloride (NaCl). As chlorine is more reactive than bromine, bromine cannot displace chlorine from the compound. Thus, no reaction will occur.
Conclusion: No reaction.
### Reaction 4: [tex]\( CuF_2 + I_2 \rightarrow \)[/tex]
Iodine (I) is less reactive than fluorine (F) in the activity series. In this scenario, for a reaction to occur, iodine would need to replace fluorine in the compound copper(II) fluoride (CuF_2). Since iodine is less reactive than fluorine, it cannot displace fluorine from the compound. Thus, no reaction will occur.
Conclusion: No reaction.
### Summary of Reactions:
- Reaction 1: [tex]\( CuI_2 + Br_2 \rightarrow \)[/tex] No reaction
- Reaction 2: [tex]\( Cl_2 + AlF_3 \rightarrow \)[/tex] No reaction
- Reaction 3: [tex]\( Br_2 + NaCl \rightarrow \)[/tex] No reaction
- Reaction 4: [tex]\( CuF_2 + I_2 \rightarrow \)[/tex] No reaction
Therefore, none of the given reactions will form any products based on the activity series [tex]\( F > Cl > Br > I \)[/tex].
