Write the following equation in standard form: [tex]\( x^5 + 2x^3 + 6x + \frac{1}{5} \)[/tex]

A. [tex]\( 6x + 2x^3 + x^6 + \frac{1}{5} \)[/tex]

B. It already is in standard form

C. [tex]\( 6x + 2x^3 + x^3 + \frac{1}{5} + 0x^2 \)[/tex]

D. [tex]\( \frac{1}{5} + 6x + 0x^2 + 2x^3 + x^5 \)[/tex]



Answer :

To determine whether the given polynomial [tex]\(x^5 + 2 x^3 + 6 x + \frac{1}{5}\)[/tex] is in standard form, we should rewrite the polynomial such that the terms are arranged in descending order of the powers of [tex]\(x\)[/tex].

Let's examine the polynomial step-by-step:

1. The given polynomial is: [tex]\(x^5 + 2 x^3 + 6 x + \frac{1}{5}\)[/tex].
2. The highest power of [tex]\(x\)[/tex] is [tex]\(x^5\)[/tex], so it appears first.
3. Next, we have the term with [tex]\(x^3\)[/tex], which is [tex]\(2 x^3\)[/tex].
4. Then comes the [tex]\(x\)[/tex] term, which is [tex]\(6 x\)[/tex].
5. Finally, the constant term, [tex]\(\frac{1}{5}\)[/tex], comes at the end.

When we look at the polynomial [tex]\(x^5 + 2 x^3 + 6 x + \frac{1}{5}\)[/tex], we see that the terms are already arranged in descending order of their powers. Thus, it is in the standard form.

So the correct answer is:
B. It already is in standard form

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