Answer :
To solve the system of linear equations
[tex]\[ \begin{cases} 4x - 6y = -6 \\ 8x + 3y = -7 \end{cases} \][/tex]
we follow these steps:
1. Equation Rearrangement:
We already have the system in standard form [tex]\(Ax + By = C\)[/tex]. We can start solving it by any preferred method such as substitution or elimination.
2. Elimination Method:
We aim to eliminate one of the variables by adding or subtracting the equations. First, let's multiply the first equation by 2 to align the coefficients of [tex]\(x\)[/tex] in both equations.
[tex]\[ 2 \times (4x - 6y) = 2 \times (-6) \][/tex]
This simplifies to:
[tex]\[ 8x - 12y = -12 \][/tex]
Now we have:
[tex]\[ \begin{cases} 8x - 12y = -12 \\ 8x + 3y = -7 \end{cases} \][/tex]
3. Subtract the Second Equation from the First:
[tex]\[ (8x - 12y) - (8x + 3y) = -12 - (-7) \][/tex]
Simplify this:
[tex]\[ 8x - 12y - 8x - 3y = -12 + 7 \][/tex]
[tex]\[ -15y = -5 \][/tex]
Solving for [tex]\(y\)[/tex]:
[tex]\[ y = \frac{-5}{-15} = \frac{1}{3} \][/tex]
4. Substitute [tex]\(y\)[/tex] back into one of the original equations to solve for [tex]\(x\)[/tex]:
Let's use the first equation [tex]\(4x - 6y = -6\)[/tex]:
[tex]\[ 4x - 6 \left(\frac{1}{3}\right) = -6 \][/tex]
Simplify the equation:
[tex]\[ 4x - 2 = -6 \][/tex]
Add 2 to both sides:
[tex]\[ 4x = -6 + 2 \][/tex]
[tex]\[ 4x = -4 \][/tex]
Solve for [tex]\(x\)[/tex]:
[tex]\[ x = \frac{-4}{4} = -1 \][/tex]
Therefore, the solution to the system of equations is:
[tex]\[ (x, y) = \left(-1, \frac{1}{3}\right) \][/tex]
[tex]\[ \begin{cases} 4x - 6y = -6 \\ 8x + 3y = -7 \end{cases} \][/tex]
we follow these steps:
1. Equation Rearrangement:
We already have the system in standard form [tex]\(Ax + By = C\)[/tex]. We can start solving it by any preferred method such as substitution or elimination.
2. Elimination Method:
We aim to eliminate one of the variables by adding or subtracting the equations. First, let's multiply the first equation by 2 to align the coefficients of [tex]\(x\)[/tex] in both equations.
[tex]\[ 2 \times (4x - 6y) = 2 \times (-6) \][/tex]
This simplifies to:
[tex]\[ 8x - 12y = -12 \][/tex]
Now we have:
[tex]\[ \begin{cases} 8x - 12y = -12 \\ 8x + 3y = -7 \end{cases} \][/tex]
3. Subtract the Second Equation from the First:
[tex]\[ (8x - 12y) - (8x + 3y) = -12 - (-7) \][/tex]
Simplify this:
[tex]\[ 8x - 12y - 8x - 3y = -12 + 7 \][/tex]
[tex]\[ -15y = -5 \][/tex]
Solving for [tex]\(y\)[/tex]:
[tex]\[ y = \frac{-5}{-15} = \frac{1}{3} \][/tex]
4. Substitute [tex]\(y\)[/tex] back into one of the original equations to solve for [tex]\(x\)[/tex]:
Let's use the first equation [tex]\(4x - 6y = -6\)[/tex]:
[tex]\[ 4x - 6 \left(\frac{1}{3}\right) = -6 \][/tex]
Simplify the equation:
[tex]\[ 4x - 2 = -6 \][/tex]
Add 2 to both sides:
[tex]\[ 4x = -6 + 2 \][/tex]
[tex]\[ 4x = -4 \][/tex]
Solve for [tex]\(x\)[/tex]:
[tex]\[ x = \frac{-4}{4} = -1 \][/tex]
Therefore, the solution to the system of equations is:
[tex]\[ (x, y) = \left(-1, \frac{1}{3}\right) \][/tex]