Given the equation:

[tex]\[ x^2 + 8x + 10 = (x + p)^2 + q \][/tex]

Find the value of [tex]\( p \)[/tex] and [tex]\( q \)[/tex].



Answer :

To solve for [tex]\( p \)[/tex] and [tex]\( q \)[/tex] in the given equation [tex]\( x^2 + 8x + 10 = (x + p)^2 + q \)[/tex], we will proceed step by step.

1. Step 1: Expand [tex]\( (x + p)^2 \)[/tex]

Start by expanding the expression on the right-hand side of the equation:

[tex]\[ (x + p)^2 = x^2 + 2px + p^2 \][/tex]

Therefore, we can rewrite the right-hand side of the equation as:

[tex]\[ (x + p)^2 + q = x^2 + 2px + p^2 + q \][/tex]

2. Step 2: Set the expanded form equal to the original equation

Now, we equate the left-hand side [tex]\( x^2 + 8x + 10 \)[/tex] with the expanded form [tex]\( x^2 + 2px + p^2 + q \)[/tex]:

[tex]\[ x^2 + 8x + 10 = x^2 + 2px + p^2 + q \][/tex]

3. Step 3: Compare coefficients

To solve for [tex]\( p \)[/tex] and [tex]\( q \)[/tex], compare the coefficients of [tex]\( x \)[/tex] and the constant terms on both sides.

- Coefficient of [tex]\( x^2 \)[/tex]:
On both sides, the coefficient is 1, so this term cancels out.

- Coefficient of [tex]\( x \)[/tex]:
[tex]\[ 8 = 2p \][/tex]

Solve for [tex]\( p \)[/tex]:

[tex]\[ p = \frac{8}{2} = 4 \][/tex]

- Constant terms:
[tex]\[ 10 = p^2 + q \][/tex]

Substitute [tex]\( p = 4 \)[/tex] into this equation:

[tex]\[ 10 = 4^2 + q \][/tex]

Which simplifies to:

[tex]\[ 10 = 16 + q \][/tex]

Solving for [tex]\( q \)[/tex]:

[tex]\[ q = 10 - 16 \][/tex]

Therefore:

[tex]\[ q = -6 \][/tex]

4. Step 4: Conclusion

We have found the values of [tex]\( p \)[/tex] and [tex]\( q \)[/tex]:

[tex]\[ p = 4 \][/tex]

[tex]\[ q = -6 \][/tex]

Thus, the solution is:
[tex]\( p = 4 \)[/tex] and [tex]\( q = -6 \)[/tex].