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Lamar and Mimi are in the same math class. The table shows their scores on 6 math tests.

| Lamar | Mimi |
|-------|------|
| 93 | 90 |
| 97 | 93 |
| 96 | 90 |
| 95 | 91 |
| 94 | 90 |
| 98 | 100 |

The best measure of center in this scenario is the [ ] , and its values for Lamar's and Mimi's data are [ ] and [ ] respectively. When comparing the measures of center, we can conclude that generally Lamar's scores are [ ] Mimi's.



Answer :

GinnyAnswer
Let's examine the data and follow the step-by-step solution to fill in the blanks appropriately.

1. Lamar and Mimi's Scores:
- Lamar: 93, 97, 96, 95, 94, 98
- Mimi: 90, 93, 90, 91, 90, 100

2. Calculating the Measure of Center (Mean):

- First, we calculate the mean for Lamar's scores:
[tex]\[ \text{Mean for Lamar} = \frac{93 + 97 + 96 + 95 + 94 + 98}{6} = \frac{573}{6} = 95.5 \][/tex]

- Next, we calculate the mean for Mimi's scores:
[tex]\[ \text{Mean for Mimi} = \frac{90 + 93 + 90 + 91 + 90 + 100}{6} = \frac{554}{6} \approx 92.333 \][/tex]

3. Conclusion:
- The best measure of center in this scenario is the mean.
- The mean values for Lamar's and Mimi's data are 95.5 and 92.333 respectively.
- When comparing the measures of center, we can conclude that generally Lamar's scores are higher than Mimi's.

Putting this all together, we complete the sentence as follows:

---

The best measure of center in this scenario is the mean, and its values for Lamar's and Mimi's data are 95.5 and 92.333 respectively. When comparing the measures of center, we can conclude that generally Lamar's scores are higher than Mimi's.

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