To determine which reactions will occur, we need to examine the reactivity of the elements involved in each reaction using the given activity series for metals and nonmetals.
1. Reaction 1:
[tex]\[ 2 \, \text{NaBr} + \text{I}_2 \rightarrow 2 \, \text{NaI} + \text{Br}_2 \][/tex]
- Iodine (I[tex]\(_2\)[/tex]) can displace Bromine (Br) if Iodine is less reactive than Bromine.
- According to the nonmetals activity series, Bromine (Br) is more reactive than Iodine (I).
- Since Iodine is less reactive, it can displace Bromine in this reaction.
Reaction 1 will occur.
2. Reaction 2:
[tex]\[ 2 \, \text{Fe} + \text{Al}_2\text{O}_3 \rightarrow 2 \, \text{Al} + \text{Fe}_2\text{O}_3 \][/tex]
- To displace Aluminum (Al) from its oxide, Iron (Fe) must be more reactive than Aluminum.
- According to the metals activity series, Aluminum (Al) is more reactive than Iron (Fe).
- Therefore, Iron cannot displace Aluminum in this reaction.
Reaction 2 will not occur.
3. Reaction 3:
[tex]\[ 2 \, \text{AgNO}_3 + \text{Ni} \rightarrow \text{Ni}(\text{NO}_3)_2 + 2 \, \text{Ag} \][/tex]
- Nickel (Ni) can displace Silver (Ag) if Nickel is more reactive than Silver.
- According to the metals activity series, Nickel (Ni) is more reactive than Silver (Ag).
- Thus, Nickel can displace Silver in this reaction.
Reaction 3 will occur.
4. Reaction 4:
[tex]\[ \text{Pb} + \text{Zn}(\text{C}_2\text{H}_3\text{O}_2)_2 \rightarrow \text{Zn} + \text{Pb}(\text{C}_2\text{H}_3\text{O}_2)_2 \][/tex]
- Lead (Pb) can displace Zinc (Zn) if Lead is more reactive than Zinc.
- According to the metals activity series, Zinc (Zn) is more reactive than Lead (Pb).
- Therefore, Lead cannot displace Zinc in this reaction.
Reaction 4 will not occur.
Based on the above analysis:
- Reaction 1 occurs.
- Reaction 2 does not occur.
- Reaction 3 occurs.
- Reaction 4 does not occur.
The binary representation of whether the reactions occur (1 for occurrence, 0 for non-occurrence) will be:
[tex]\[ [1, 0, 1, 0] \][/tex]
Therefore, the correct and complete outcome is:
- Reaction 1: True
- Reaction 2: False
- Reaction 3: True
- Reaction 4: False
- Binary result: [1, 1, 0 ]
