The hypotenuse of a [tex]\(45^\circ-45^\circ-90^\circ\)[/tex] triangle measures 4 cm. What is the length of one leg of the triangle?

A. [tex]\(2 \, \text{cm}\)[/tex]

B. [tex]\(2 \sqrt{2} \, \text{cm}\)[/tex]

C. [tex]\(4 \, \text{cm}\)[/tex]

D. [tex]\(4 \sqrt{2} \, \text{cm}\)[/tex]



Answer :

To solve for the length of one leg of a [tex]\(45^\circ-45^\circ-90^\circ\)[/tex] triangle where the hypotenuse is given as 4 cm, we can use properties specific to this type of right triangle.

1. Understand the Triangle: In a [tex]\(45^\circ-45^\circ-90^\circ\)[/tex] triangle, the two legs are of equal length since the angles opposite these legs are both [tex]\(45^\circ\)[/tex].

2. Relationship Between the Legs and Hypotenuse: The hypotenuse ([tex]\(c\)[/tex]) of a [tex]\(45^\circ-45^\circ-90^\circ\)[/tex] triangle is equal to the leg length ([tex]\(a\)[/tex]) multiplied by [tex]\(\sqrt{2}\)[/tex]. This can be expressed as:
[tex]\[ c = a\sqrt{2} \][/tex]

3. Plug in the Given Hypotenuse: Here, the hypotenuse ([tex]\(c\)[/tex]) is 4 cm. Thus, we set up the equation:
[tex]\[ 4 = a\sqrt{2} \][/tex]

4. Solve for the Leg Length [tex]\(a\)[/tex]: To find the length of one of the legs, solve for [tex]\(a\)[/tex]:
[tex]\[ a = \frac{4}{\sqrt{2}} \][/tex]

5. Rationalize the Denominator (optional but often done in math): To rationalize the denominator, multiply by [tex]\(\frac{\sqrt{2}}{\sqrt{2}}\)[/tex]:
[tex]\[ a = \frac{4 \cdot \sqrt{2}}{\sqrt{2} \cdot \sqrt{2}} = \frac{4\sqrt{2}}{2} = 2\sqrt{2} \][/tex]

Thus, the length of one leg of the triangle is:
[tex]\[ 2\sqrt{2} \text{ cm} \][/tex]

Therefore, the correct answer is:
[tex]\[ 2 \sqrt{2} \text{ cm} \][/tex]