Triangle [tex]\(ABC\)[/tex] is located at points [tex]\(A=(-6,4)\)[/tex], [tex]\(B=(2,4)\)[/tex], and [tex]\(C=(1,-2)\)[/tex] and has been dilated from the origin by a scale factor of 0.5.

a. Determine the coordinates of the dilated triangle [tex]\(A'B'C'\)[/tex].



Answer :

To determine the coordinates of the dilated triangle [tex]\( A' B' C' \)[/tex] with the original triangle [tex]\( A B C \)[/tex] located at points [tex]\( A = (-6, 4) \)[/tex], [tex]\( B = (2, 4) \)[/tex], and [tex]\( C = (1, -2) \)[/tex], and given that the dilation is from the origin by a scale factor of 0.5, we should follow these steps:

1. Dilate point A:
- Original coordinates of [tex]\( A \)[/tex]: [tex]\( (-6, 4) \)[/tex]
- Scale factor: 0.5
- New coordinates of [tex]\( A' \)[/tex]: Multiply each coordinate of [tex]\( A \)[/tex] by the scale factor [tex]\( 0.5 \)[/tex]:
[tex]\[ A' = (-6 \times 0.5, 4 \times 0.5) = (-3, 2) \][/tex]

2. Dilate point B:
- Original coordinates of [tex]\( B \)[/tex]: [tex]\( (2, 4) \)[/tex]
- Scale factor: 0.5
- New coordinates of [tex]\( B' \)[/tex]: Multiply each coordinate of [tex]\( B \)[/tex] by the scale factor [tex]\( 0.5 \)[/tex]:
[tex]\[ B' = (2 \times 0.5, 4 \times 0.5) = (1, 2) \][/tex]

3. Dilate point C:
- Original coordinates of [tex]\( C \)[/tex]: [tex]\( (1, -2) \)[/tex]
- Scale factor: 0.5
- New coordinates of [tex]\( C' \)[/tex]: Multiply each coordinate of [tex]\( C \)[/tex] by the scale factor [tex]\( 0.5 \)[/tex]:
[tex]\[ C' = (1 \times 0.5, -2 \times 0.5) = (0.5, -1) \][/tex]

So, the coordinates of the dilated triangle [tex]\( A' B' C' \)[/tex] are:
[tex]\[ A' = (-3.0, 2.0), \quad B' = (1.0, 2.0), \quad C' = (0.5, -1.0) \][/tex]

These calculations give us the new positions of the vertices after dilation.