The junior and senior classes at Central High School were asked to choose a destination for a field trip. The results are shown in the given two-way frequency table.

Central High School Field Trip Destination

[tex]\[
\begin{array}{|c|c|c|c|c|}
\cline{2-5}
\multicolumn{1}{c|}{} & \text{Amusement Park} & \text{Museum} & \text{Broadway Show} & \text{Total} \\
\hline
\text{Juniors} & 57 & 21 & 42 & 120 \\
\hline
\text{Seniors} & 64 & 44 & 58 & 166 \\
\hline
\text{Total} & 121 & 65 & 100 & 286 \\
\hline
\end{array}
\][/tex]

What percentage of surveyed students chose the amusement park?

A. 47.50%

B. 19.93%

C. 38.55%

D. 42.31%



Answer :

To determine what percentage of the surveyed students chose the amusement park, we need to carefully analyze the given data.

1. The total number of students surveyed is found in the bottom right cell of the table, which is 286 students.

2. The number of students who chose the amusement park is found in the first column under the "Amusement Park" header, which is 121 students.

The percentage of students who chose the amusement park can be calculated using the formula:
[tex]\[ \text{Percentage} = \left( \frac{\text{Number of students who chose the amusement park}}{\text{Total number of students surveyed}} \right) \times 100 \][/tex]

Plugging in the values from the table:
[tex]\[ \text{Percentage} = \left( \frac{121}{286} \right) \times 100 \][/tex]

This calculation yields a result of approximately 42.31%.

Thus, the correct percentage of students who chose the amusement park is:
[tex]\[ \boxed{42.31\%} \][/tex]
Therefore, the correct answer is:
D. [tex]$\quad 42.31 \%$[/tex]