To identify whether a compound is organic or inorganic, we need to look at the composition of each compound. Generally, organic compounds contain carbon atoms bonded to hydrogen atoms, often in combination with other elements such as oxygen, nitrogen, sulfur, and phosphorus. Inorganic compounds, on the other hand, usually do not contain these carbon-hydrogen bonds, although there are some exceptions.
Let's examine each of the given compounds:
A. [tex]\(C_6H_{12}O_6\)[/tex] - This is Glucose. It's a sugar molecule, which is a carbohydrate. Carbohydrates are a class of organic compounds.
B. [tex]\(KH_2PO_4\)[/tex] - This is Potassium dihydrogen phosphate. It contains potassium (K), hydrogen (H), phosphorus (P), and oxygen (O). This does not fit the primary structure of organic compounds which are based on carbon chains or rings.
C. [tex]\(CH_3COOH\)[/tex] - This is Acetic acid. It contains carbon-hydrogen bonds and is a simple carboxylic acid, which is classified under organic compounds.
D. [tex]\(C_2H_6\)[/tex] - This is Ethane. It contains carbon and hydrogen atoms, specifically a chain of two carbon atoms bonded to six hydrogen atoms. This is an alkane, which is definitely an organic compound.
E. [tex]\(C_2H_5OH\)[/tex] - This is Ethanol. It consists of carbon, hydrogen, and oxygen elements, forming an alcohol group which classifies it as an organic compound.
Upon carefully reviewing these compounds, we observe that most contain carbon-hydrogen bonds and fall under the category of organic compounds. However, [tex]\(KH_2PO_4\)[/tex] does not follow this pattern and qualifies as an inorganic compound.
Thus, the correct answer is:
B. [tex]\(KH_2PO_4\)[/tex]
Considering these points, we recognize [tex]\(KH_2PO_4\)[/tex] (Potassium dihydrogen phosphate) as the inorganic compound among the options provided. Therefore, the correct choice is [tex]\(2\)[/tex].
