Factor [tex]\(3x^3 - 15x^2 + 18x\)[/tex]:

A. [tex]\(3(x^2 - 2)(x - 3)\)[/tex]

B. [tex]\(3x(x + 2)(x - 3)\)[/tex]

C. [tex]\(3x(x - 2)(x - 3)\)[/tex]

D. [tex]\(3(x^2 + 2)(x - 3)\)[/tex]



Answer :

To factor the polynomial [tex]\( 3x^3 - 15x^2 + 18x \)[/tex], let's follow the step-by-step process.

1. Identify the common factor:
The polynomial [tex]\( 3x^3 - 15x^2 + 18x \)[/tex] has a common factor in each term. We can see that each term is divisible by [tex]\( 3x \)[/tex].

[tex]\[ 3x^3 - 15x^2 + 18x = 3x(x^2 - 5x + 6) \][/tex]

2. Factor the quadratic:
Next, we need to factor the quadratic expression [tex]\( x^2 - 5x + 6 \)[/tex]. To do this, we'll find two numbers that multiply to the constant term (6) and add up to the coefficient of the linear term (-5).

The pairs of numbers that multiply to 6 are:
- [tex]\( (1, 6) \)[/tex]
- [tex]\( (2, 3) \)[/tex]

Out of these pairs, [tex]\( -2 \)[/tex] and [tex]\( -3 \)[/tex] add up to [tex]\( -5 \)[/tex]:

[tex]\[ -2 \cdot -3 = 6 \quad \text{and} \quad -2 + (-3) = -5 \][/tex]

So, [tex]\( x^2 - 5x + 6 \)[/tex] factors to:

[tex]\[ (x - 2)(x - 3) \][/tex]

3. Combine the factors:
Now, we substitute the factored quadratic expression back into the initial factor:

[tex]\[ 3x(x^2 - 5x + 6) = 3x(x - 2)(x - 3) \][/tex]

Therefore, the factorized form of the polynomial [tex]\( 3x^3 - 15x^2 + 18x \)[/tex] is:

[tex]\[ 3x(x - 2)(x - 3) \][/tex]

So, the correct answer is:

C. [tex]\( 3x(x-2)(x-3) \)[/tex]

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