Answer :

Let's carefully analyze the given system of equations:

[tex]\[ \begin{array}{l} y = -1 \\ y = -3 \\ y = 1 \\ y = 3 \end{array} \][/tex]

Here we have four equations, each giving a different value for [tex]\( y \)[/tex]:
1. [tex]\( y = -1 \)[/tex]
2. [tex]\( y = -3 \)[/tex]
3. [tex]\( y = 1 \)[/tex]
4. [tex]\( y = 3 \)[/tex]

For a system of equations to have a consistent solution, all equations must be satisfied by the same value of [tex]\( y \)[/tex]. However, in this system:

- The first equation states [tex]\( y = -1 \)[/tex],
- The second equation states [tex]\( y = -3 \)[/tex],
- The third equation states [tex]\( y = 1 \)[/tex],
- The fourth equation states [tex]\( y = 3 \)[/tex].

It is impossible for [tex]\( y \)[/tex] to be simultaneously [tex]\(-1\)[/tex], [tex]\(-3\)[/tex], [tex]\(1\)[/tex], and [tex]\(3\)[/tex] at the same time. These values are mutually exclusive and contradict each other.

Hence, this system of equations does not have a consistent or unique solution. In other words, there is no single value of [tex]\( y \)[/tex] that satisfies all four equations simultaneously.

Thus, the conclusion is:
There is no consistent solution for [tex]\( y \)[/tex].

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