An eagle carries a fish up 50 m into the sky using 90 N of force. How much work did the eagle do on the fish?

(Work: [tex]\( W = F \cdot d \)[/tex] )

A. 40 J
B. 59 J
C. 140 J
D. 4500 J



Answer :

To determine how much work the eagle did on the fish, you need to use the formula for work, which is given by:

[tex]\[ W = F \times d \][/tex]

where:
- [tex]\( W \)[/tex] is the work done,
- [tex]\( F \)[/tex] is the force applied,
- [tex]\( d \)[/tex] is the distance over which the force is applied.

In this problem:
- The force [tex]\( F \)[/tex] applied by the eagle is [tex]\( 90 \)[/tex] Newtons,
- The distance [tex]\( d \)[/tex] the fish is carried is [tex]\( 50 \)[/tex] meters.

Substitute these values into the formula:

[tex]\[ W = 90 \, \text{N} \times 50 \, \text{m} \][/tex]

[tex]\[ W = 4500 \, \text{J} \][/tex]

So, the amount of work the eagle did on the fish is [tex]\( 4500 \)[/tex] Joules (J).

Therefore, the correct answer is:

[tex]\[ \boxed{4500 \, \text{J}} \][/tex]