To determine how much work the eagle did on the fish, you need to use the formula for work, which is given by:
[tex]\[ W = F \times d \][/tex]
where:
- [tex]\( W \)[/tex] is the work done,
- [tex]\( F \)[/tex] is the force applied,
- [tex]\( d \)[/tex] is the distance over which the force is applied.
In this problem:
- The force [tex]\( F \)[/tex] applied by the eagle is [tex]\( 90 \)[/tex] Newtons,
- The distance [tex]\( d \)[/tex] the fish is carried is [tex]\( 50 \)[/tex] meters.
Substitute these values into the formula:
[tex]\[ W = 90 \, \text{N} \times 50 \, \text{m} \][/tex]
[tex]\[ W = 4500 \, \text{J} \][/tex]
So, the amount of work the eagle did on the fish is [tex]\( 4500 \)[/tex] Joules (J).
Therefore, the correct answer is:
[tex]\[ \boxed{4500 \, \text{J}} \][/tex]
