The soccer team is planning to sell health bars for a fundraiser. The prices of purchasing health bars from two different companies are represented by the system of equations shown, where [tex]\(x\)[/tex] is the number of bars purchased and [tex]\(y\)[/tex] is the total cost in dollars.

Company A: [tex]\(y = 0.75x\)[/tex]
Company B: [tex]\(y = 10 + 0.50x\)[/tex]

How many bars would the team need to purchase from each company in order for the total cost to be equal?

A. 6
B. 8
C. 30
D. 40



Answer :

To determine how many bars the soccer team needs to purchase for the total cost from both companies to be equal, let's solve the given system of linear equations step-by-step.

We have two companies with the following cost equations:
- Company A: [tex]\( y_A = 0.75x \)[/tex]
- Company B: [tex]\( y_B = 10 + 0.50x \)[/tex]

We need to find the value of [tex]\( x \)[/tex] (the number of health bars) for which the total cost from both companies is the same. Therefore, we set the equations equal to each other:

[tex]\[ 0.75x = 10 + 0.50x \][/tex]

To isolate [tex]\( x \)[/tex], we first subtract [tex]\( 0.50x \)[/tex] from both sides of the equation:

[tex]\[ 0.75x - 0.50x = 10 \][/tex]

This simplifies to:

[tex]\[ 0.25x = 10 \][/tex]

Next, we solve for [tex]\( x \)[/tex] by dividing both sides by 0.25:

[tex]\[ x = \frac{10}{0.25} \][/tex]

Calculating the right-hand side:

[tex]\[ x = 40 \][/tex]

So, the soccer team needs to purchase 40 health bars for the total cost from both companies to be equal. Therefore, the correct answer is:

40

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