Solve the inequality. Use [tex]$\ \textless \ =$[/tex] for [tex]$\leq$[/tex] and [tex]$\ \textgreater \ =$[/tex] for [tex]$\geq$[/tex].

[tex]\[
\frac{1}{3} x \ \textless \ -2
\][/tex]

Answer here: ______________



Answer :

Sure! Let's solve the inequality step by step:

Given inequality:
[tex]\[ \frac{1}{3} x < -2 \][/tex]

1. Isolate the Variable:
- To solve for [tex]\( x \)[/tex], we need to isolate [tex]\( x \)[/tex]. Since [tex]\( x \)[/tex] is currently multiplied by [tex]\(\frac{1}{3}\)[/tex], we can eliminate the fraction by multiplying both sides of the inequality by the reciprocal of [tex]\(\frac{1}{3}\)[/tex], which is 3.

2. Multiply Both Sides by 3:
- Multiplying both sides by 3, we get:
[tex]\[ \frac{1}{3} x \cdot 3 < -2 \cdot 3 \][/tex]

3. Simplify:
- Simplify the left-hand side and the right-hand side of the inequality:
[tex]\[ x < -6 \][/tex]

Therefore, the solution to the inequality [tex]\(\frac{1}{3} x < -2\)[/tex] is:

[tex]\[ x < -6 \][/tex]

This means that [tex]\( x \)[/tex] must be any number less than [tex]\(-6\)[/tex].