Answer:
The circle's center is at (-4,0) and has a radius of 4.
Step-by-step explanation:
Recall the format of the equation of a circle,
[tex](x-h)^2+(y-k)^2=r^2[/tex],
where (h, k) is the center of the circle and r is the radius.
We're given the equation,
[tex](x+4)^2+y^2=16[/tex].
Since there is no integer after the y squared term, k must be 0 so, the center is at (-4, 0).
Since 16 is the radius' value squared, taking the square root of 16 will give us the length of the circle's radius or 4.