Certainly! Let's solve this step by step.
We start with the given single displacement reaction involving sodium bromide and chlorine gas:
[tex]\[ 2 \text{NaBr} + \text{Cl}_2 \rightarrow \][/tex]
In a single displacement reaction, chlorine (Cl₂) will displace bromine (Br) in sodium bromide (NaBr). As a result, bromine is displaced from the compound, and chlorine will replace it.
1. Displacing Bromine:
Bromine (Br) atoms will be displaced and will pair up to form bromine gas (Br₂).
[tex]\[ \text{Br}_2 \][/tex]
2. Forming Sodium Chloride:
The sodium ions (Na⁺) will pair up with the chlorine atoms to form sodium chloride (NaCl).
[tex]\[ \text{NaCl} \][/tex]
Based on the stoichiometry of the reaction, we need to balance the equation accurately:
[tex]\[ 2 \text{NaBr} + \text{Cl}_2 \rightarrow 2 \text{NaCl} + \text{Br}_2 \][/tex]
The balanced chemical equation is:
[tex]\[ 2 \text{NaBr} + \text{Cl}_2 \rightarrow 2 \text{NaCl} + \text{Br}_2 \][/tex]
Thus, the correct chemical symbols to complete the equation are:
[tex]\[ 2 \text{NaBr} + \text{Cl}_2 \rightarrow 2 \boxed{\text{NaCl}} + \boxed{\text{Br}_2} \][/tex]
So, the completed equation is:
[tex]\[ 2 \text{NaBr} + \text{Cl}_2 \rightarrow 2 \text{NaCl} + \text{Br}_2 \][/tex]
The symbols that fill in the blanks are "NaCl" and "Br₂".
