Consider the reaction [tex]\( H_2(g) + I_2(g) \leftrightarrow 2 HI(g) \)[/tex].

What is the reaction quotient, [tex]\( Q \)[/tex], for this system when [tex]\([H_2] = 0.100 \, M\)[/tex], [tex]\([I_2] = 0.200 \, M\)[/tex], and [tex]\([HI] = 3.50 \, M\)[/tex]?

A. 87.5
B. 175
C. 350
D. 613



Answer :

To determine the reaction quotient, [tex]\( Q \)[/tex], for the given reaction:

[tex]\[ \text{H}_2(g) + \text{I}_2(g) \leftrightarrow 2 \text{HI}(g) \][/tex]

you need to use the formula for the reaction quotient. For the reaction [tex]\( \text{H}_2 + \text{I}_2 \leftrightarrow 2 \text{HI} \)[/tex], the expression for [tex]\( Q \)[/tex] is:

[tex]\[ Q = \frac{[\text{HI}]^2}{[\text{H}_2] \cdot [\text{I}_2]} \][/tex]

Given the concentrations:
[tex]\[ [\text{H}_2] = 0.100 \, M \][/tex]
[tex]\[ [\text{I}_2] = 0.200 \, M \][/tex]
[tex]\[ [\text{HI}] = 3.50 \, M \][/tex]

Let's substitute these values into the formula.

1. Calculate the numerator of the reaction quotient:
[tex]\[ [\text{HI}]^2 = (3.50 \, M)^2 \][/tex]
[tex]\[ [\text{HI}]^2 = 12.25 \, M^2 \][/tex]

2. Calculate the denominator of the reaction quotient:
[tex]\[ [\text{H}_2] \cdot [\text{I}_2] = 0.100 \, M \cdot 0.200 \, M \][/tex]
[tex]\[ [\text{H}_2] \cdot [\text{I}_2] = 0.0200 \, M^2 \][/tex]

3. Now, divide the numerator by the denominator to find [tex]\( Q \)[/tex]:
[tex]\[ Q = \frac{[\text{HI}]^2}{[\text{H}_2] \cdot [\text{I}_2]} = \frac{12.25 \, M^2}{0.0200 \, M^2} \][/tex]
[tex]\[ Q = 612.5 \][/tex]

Therefore, the reaction quotient [tex]\( Q \)[/tex] for this system is closest to:

[tex]\[ \boxed{613} \][/tex]

So the correct answer is 613.

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