Select the correct answer.

[tex]$\overline{JK}$[/tex] is dilated by a scale factor of [tex]$n$[/tex] with the origin as the center of dilation, resulting in the image [tex]$\overline{J'K'}$[/tex]. The slope of [tex]$\overline{JK}$[/tex] is [tex]$m$[/tex]. If the length of [tex]$\overline{JK}$[/tex] is 1, what is the length of [tex]$\overline{J'K'}$[/tex]?

A. [tex]$m \times n \times 1$[/tex]
B. [tex]$(m+n) \times 1$[/tex]
C. [tex]$m \times 1$[/tex]
D. [tex]$n \times 1$[/tex]



Answer :

To determine the length of the segment [tex]$\overline{J^{\prime} K^{\prime}}$[/tex] after dilation by a scale factor of [tex]$n$[/tex] with the origin as the center of dilation, let's follow these steps:

1. Understand the concept of dilation:
Dilation is a transformation that produces an image that is the same shape as the original, but is a different size. The size change is determined by a scale factor, and the image is positioned relative to a fixed center point.

2. Scale factor and segment length:
If [tex]$\overline{J K}$[/tex] is a segment with a length of 1 unit and it is dilated by a scale factor of [tex]$n$[/tex], the length of the resulting segment [tex]$\overline{J^{\prime} K^{\prime}}$[/tex] changes according to the scale factor.

3. Effect of dilation on length:
When a segment is dilated with a scale factor of [tex]$n$[/tex], the length of the new segment [tex]$\overline{J^{\prime} K^{\prime}}$[/tex] is given by multiplying the length of the original segment [tex]$\overline{J K}$[/tex] by the scale factor [tex]$n$[/tex].

4. Calculation:
- The original length of [tex]$\overline{J K}$[/tex] is 1.
- The scale factor is [tex]$n$[/tex].
- Therefore, the length of [tex]$\overline{J^{\prime} K^{\prime}} = 1 * n = n$[/tex].

Based on this understanding, the correct answer is:

D. [tex]\( n \times 1 \)[/tex]