Livia eats a chicken drumstick with 11 grams of protein. She also eats [tex]\(x\)[/tex] cheese sticks, each with 7 grams of protein. The table shows [tex]\(y\)[/tex], the total number of grams of protein that Livia will consume if she eats [tex]\(x\)[/tex] cheese sticks. Livia may eat only part of a cheese stick, so [tex]\(x\)[/tex] may not always be a whole number.

[tex]\[
\begin{tabular}{|c|c|}
\hline
$x$ & $y$ \\
\hline
0 & 11 \\
\hline
2.5 & 28.5 \\
\hline
5 & 46 \\
\hline
7 & 60 \\
\hline
\end{tabular}
\][/tex]

What is the range of the function?

A. All real numbers
B. All real numbers greater than or equal to 0
C. All real numbers greater than or equal to 11
D. All integers greater than or equal to 11



Answer :

To determine the range of the function, let's analyze the protein consumption scenario step-by-step.

1. Understanding the Components: Livia always eats a chicken drumstick which provides her with a fixed amount of protein, specifically 11 grams. This is a constant contribution to her protein intake.

2. Contribution from Cheese Sticks: In addition to the chicken drumstick, she eats [tex]\( x \)[/tex] cheese sticks. Each cheese stick contains 7 grams of protein. The quantity [tex]\( x \)[/tex] represents the number of cheese sticks and it can be any real number (including fractional parts since she can eat part of a cheese stick).

3. Total Protein Intake Calculation: The total protein intake [tex]\( y \)[/tex] can be expressed as:
[tex]\[ y = 11 + 7x \][/tex]
where:
- 11 grams come from the chicken drumstick,
- [tex]\( 7x \)[/tex] grams come from [tex]\( x \)[/tex] cheese sticks.

4. Establishing the Range of [tex]\( y \)[/tex]:
- The lowest possible value of [tex]\( x \)[/tex] is 0 (meaning no cheese sticks are eaten).
- For [tex]\( x = 0 \)[/tex], [tex]\( y = 11 + 7 \cdot 0 = 11 \)[/tex] grams.
- As [tex]\( x \)[/tex] can take on any real value including fractions and can increase indefinitely, [tex]\( y \)[/tex] will increase accordingly without any upper bound.

Thus, the function [tex]\( y = 11 + 7x \)[/tex] ranges from the minimum possible value of 11 (when [tex]\( x = 0 \)[/tex]) and can take any value greater than or equal to 11 as [tex]\( x \)[/tex] increases.

Hence, the range of the function [tex]\( y \)[/tex] is:
[tex]\[ \text{all real numbers greater than or equal to 11} \][/tex]

Therefore, the correct answer is:
[tex]\[ \boxed{\text{all real numbers greater than or equal to 11}} \][/tex]