Round all sides to the nearest tenth and all angles to the nearest degree.

A lighthouse operator sights a sailboat at an angle of depression of 16 degrees. If the sailboat is 120 feet away from the base of the lighthouse, how far is the lighthouse operator from the sailboat?

The lighthouse operator is ____ feet from the sailboat.



Answer :

Let's solve this problem step by step using trigonometry.

1. Understanding the Problem:
- We have a lighthouse and a sailboat.
- The angle of depression from the lighthouse operator to the sailboat is 16 degrees.
- The horizontal distance (distance along the base) from the base of the lighthouse to the sailboat is 120 feet.

2. Visual Representation:
- Imagine a right triangle where:
- The distance along the base to the sailboat is the adjacent side (120 feet).
- The distance from the lighthouse operator to the sailboat is the hypotenuse (which we need to find).
- The lighthouse and the line of sight to the sailboat form the right angle.

3. Using Trigonometry:
- In a right triangle, the cosine of an angle is defined as the adjacent side divided by the hypotenuse.
- Mathematically, this is:
[tex]\[ \cos(\theta) = \frac{\text{adjacent}}{\text{hypotenuse}} \][/tex]
- Here, [tex]\(\theta\)[/tex] is the angle of depression, which is 16 degrees.
- The adjacent side is 120 feet.
- Let [tex]\(d\)[/tex] be the distance from the lighthouse operator to the sailboat (the hypotenuse).

4. Set Up the Equation:
[tex]\[ \cos(16^\circ) = \frac{120}{d} \][/tex]

5. Solve for [tex]\(d\)[/tex]:
[tex]\[ d = \frac{120}{\cos(16^\circ)} \][/tex]

6. Calculate:
- From trigonometric tables or a calculator, we know [tex]\(\cos(16^\circ) \approx 0.9613\)[/tex].
- Substitute this value:
[tex]\[ d = \frac{120}{0.9613} \approx 124.8 \][/tex]

7. Conclusion:
- Thus, the distance from the lighthouse operator to the sailboat is approximately 124.8 feet.

So, the lighthouse operator is about 124.8 feet from the sailboat.