What is the [tex]\(r\)[/tex]-value of the following data, to three decimal places?

[tex]\[
\begin{tabular}{|c|c|}
\hline
$x$ & $y$ \\
\hline
4 & 2 \\
\hline
5 & 9 \\
\hline
8 & 10 \\
\hline
9 & 12 \\
\hline
13 & 23 \\
\hline
\end{tabular}
\][/tex]

A. -0.953
B. 0.908
C. -0.908
D. 0.953



Answer :

To determine the [tex]\( r \)[/tex]-value, which is the correlation coefficient, we can follow these general steps:

1. Calculate the mean of each variable:
[tex]\[ \bar{x} = \frac{4 + 5 + 8 + 9 + 13}{5} = 39 / 5 = 7.8 \][/tex]
[tex]\[ \bar{y} = \frac{2 + 9 + 10 + 12 + 23}{5} = 56 / 5 = 11.2 \][/tex]

2. Calculate the deviations from the mean for each variable:
[tex]\[ (x_i - \bar{x}): \quad 4 - 7.8, \quad 5 - 7.8, \quad 8 - 7.8, \quad 9 - 7.8, \quad 13 - 7.8 \][/tex]
[tex]\[ (y_i - \bar{y}): \quad 2 - 11.2, \quad 9 - 11.2, \quad 10 - 11.2, \quad 12 - 11.2, \quad 23 - 11.2 \][/tex]

3. Compute the products of the deviations for each pair [tex]\((x_i, y_i)\)[/tex]:
[tex]\[ (x_i - \bar{x}) \cdot (y_i - \bar{y}) \][/tex]

4. Sum up these products:
[tex]\[ \sum (x_i - \bar{x}) \cdot (y_i - \bar{y}) \][/tex]

5. Calculate the squared deviations for [tex]\(x\)[/tex] and [tex]\(y\)[/tex] respectively:
[tex]\[ \sum (x_i - \bar{x})^2 \][/tex]
[tex]\[ \sum (y_i - \bar{y})^2 \][/tex]

6. Plug these into the correlation formula:
[tex]\[ r = \frac{\sum (x_i - \bar{x}) (y_i - \bar{y})}{ \sqrt{\sum (x_i - \bar{x})^2} \sqrt{\sum (y_i - \bar{y})^2} } \][/tex]

After computing the above steps, the value obtained is:

[tex]\[ r \approx 0.953 \][/tex]

Thus, the [tex]\( r \)[/tex]-value is [tex]\( \boxed{0.953} \)[/tex].

In conclusion, the correct answer is [tex]\( D. \, 0.953 \)[/tex].