Answer :
To find the domain of the composite function [tex]\( (f \circ g)(x) \)[/tex], we need to consider the domains of both functions [tex]\( f(x) \)[/tex] and [tex]\( g(x) \)[/tex].
1. Find the domain of [tex]\( g(x) \)[/tex]:
[tex]\[ g(x) = \sqrt{2x + 4} \][/tex]
For [tex]\( g(x) \)[/tex] to be defined, the expression inside the square root must be non-negative:
[tex]\[ 2x + 4 \geq 0 \][/tex]
Solving this inequality:
[tex]\[ 2x \geq -4 \][/tex]
[tex]\[ x \geq -2 \][/tex]
Thus, the domain of [tex]\( g(x) \)[/tex] is [tex]\( x \geq -2 \)[/tex].
2. Find the domain of [tex]\( f(g(x)) \)[/tex]:
[tex]\[ f(g(x)) = f(\sqrt{2x + 4}) = \frac{1}{7\sqrt{2x + 4} - 14} \][/tex]
For [tex]\( f(g(x)) \)[/tex] to be defined, the denominator must not be zero:
[tex]\[ 7\sqrt{2x + 4} - 14 \neq 0 \][/tex]
Solving for when this is zero:
[tex]\[ 7\sqrt{2x + 4} = 14 \][/tex]
[tex]\[ \sqrt{2x + 4} = 2 \][/tex]
Squaring both sides:
[tex]\[ 2x + 4 = 4 \][/tex]
[tex]\[ 2x = 0 \][/tex]
[tex]\[ x = 0 \][/tex]
Therefore, [tex]\( x = 0 \)[/tex] must be excluded from the domain.
3. Combine the conditions:
The domain of [tex]\( g(x) \)[/tex] is [tex]\( x \geq -2 \)[/tex], but we also have to exclude the value where the denominator of [tex]\( f(g(x)) \)[/tex] becomes zero, which is [tex]\( x = 0 \)[/tex].
Hence, the domain of [tex]\( (f \circ g)(x) \)[/tex] is:
[tex]\[ \text{All real numbers } x \geq -2 \text{ other than 0} \][/tex]
Thus, the correct answer is:
All real numbers [tex]\( x \geq -2 \)[/tex] other than 0.
1. Find the domain of [tex]\( g(x) \)[/tex]:
[tex]\[ g(x) = \sqrt{2x + 4} \][/tex]
For [tex]\( g(x) \)[/tex] to be defined, the expression inside the square root must be non-negative:
[tex]\[ 2x + 4 \geq 0 \][/tex]
Solving this inequality:
[tex]\[ 2x \geq -4 \][/tex]
[tex]\[ x \geq -2 \][/tex]
Thus, the domain of [tex]\( g(x) \)[/tex] is [tex]\( x \geq -2 \)[/tex].
2. Find the domain of [tex]\( f(g(x)) \)[/tex]:
[tex]\[ f(g(x)) = f(\sqrt{2x + 4}) = \frac{1}{7\sqrt{2x + 4} - 14} \][/tex]
For [tex]\( f(g(x)) \)[/tex] to be defined, the denominator must not be zero:
[tex]\[ 7\sqrt{2x + 4} - 14 \neq 0 \][/tex]
Solving for when this is zero:
[tex]\[ 7\sqrt{2x + 4} = 14 \][/tex]
[tex]\[ \sqrt{2x + 4} = 2 \][/tex]
Squaring both sides:
[tex]\[ 2x + 4 = 4 \][/tex]
[tex]\[ 2x = 0 \][/tex]
[tex]\[ x = 0 \][/tex]
Therefore, [tex]\( x = 0 \)[/tex] must be excluded from the domain.
3. Combine the conditions:
The domain of [tex]\( g(x) \)[/tex] is [tex]\( x \geq -2 \)[/tex], but we also have to exclude the value where the denominator of [tex]\( f(g(x)) \)[/tex] becomes zero, which is [tex]\( x = 0 \)[/tex].
Hence, the domain of [tex]\( (f \circ g)(x) \)[/tex] is:
[tex]\[ \text{All real numbers } x \geq -2 \text{ other than 0} \][/tex]
Thus, the correct answer is:
All real numbers [tex]\( x \geq -2 \)[/tex] other than 0.