Answer :
Certainly! Let's carefully examine each reaction to predict whether it will occur based on the activity series of halogens: [tex]\( F_2 > Cl_2 > Br_2 > I_2 \)[/tex].
### Reaction 1: [tex]\( Cl_2 + 2 RbI \rightarrow 2 RbCl + I_2 \)[/tex]
1. Identify Reactants and Products:
- Reactants: [tex]\( Cl_2 \)[/tex] and [tex]\( RbI \)[/tex]
- Products: [tex]\( RbCl \)[/tex] and [tex]\( I_2 \)[/tex]
2. Understand the Activity Series:
- Chlorine ([tex]\( Cl_2 \)[/tex]) and iodine ([tex]\( I_2 \)[/tex]) are both halogens, and they are in the activity series provided.
- The activity series tells us the relative reactivity of the halogens: [tex]\( F_2 > Cl_2 > Br_2 > I_2 \)[/tex].
3. Compare Reactivities (Activity Series):
- According to the activity series, chlorine ([tex]\( Cl_2 \)[/tex]) is more reactive than iodine ([tex]\( I_2 \)[/tex]).
4. Predict the Reaction:
- Since [tex]\( Cl_2 \)[/tex] is more reactive than [tex]\( I_2 \)[/tex], [tex]\( Cl_2 \)[/tex] will displace [tex]\( I \)[/tex] in [tex]\( RbI \)[/tex], forming [tex]\( RbCl \)[/tex] and releasing [tex]\( I_2 \)[/tex].
Conclusion for Reaction 1:
- The reaction [tex]\( Cl_2 + 2 RbI \rightarrow 2 RbCl + I_2 \)[/tex] will take place.
### Reaction 2: [tex]\( I_2 + NiBr_2 \rightarrow NiI_2 + Br_2 \)[/tex]
1. Identify Reactants and Products:
- Reactants: [tex]\( I_2 \)[/tex] and [tex]\( NiBr_2 \)[/tex]
- Products: [tex]\( NiI_2 \)[/tex] and [tex]\( Br_2 \)[/tex]
2. Understand the Activity Series:
- Iodine ([tex]\( I_2 \)[/tex]) and bromine ([tex]\( Br_2 \)[/tex]) are both halogens, and they are in the activity series provided.
- The activity series tells us the relative reactivity of the halogens: [tex]\( F_2 > Cl_2 > Br_2 > I_2 \)[/tex].
3. Compare Reactivities (Activity Series):
- According to the activity series, iodine ([tex]\( I_2 \)[/tex]) is less reactive than bromine ([tex]\( Br_2 \)[/tex]).
4. Predict the Reaction:
- Since [tex]\( I_2 \)[/tex] is less reactive than [tex]\( Br_2 \)[/tex], [tex]\( I_2 \)[/tex] cannot displace [tex]\( Br \)[/tex] in [tex]\( NiBr_2 \)[/tex], so the reaction will not proceed.
Conclusion for Reaction 2:
- The reaction [tex]\( I_2 + NiBr_2 \rightarrow NiI_2 + Br_2 \)[/tex] will not take place.
### Final Prediction:
Based on the analysis:
- Reaction 1 ([tex]\( Cl_2 + 2 RbI \rightarrow 2 RbCl + I_2 \)[/tex]) will occur, indicated by 1.
- Reaction 2 ([tex]\( I_2 + NiBr_2 \rightarrow NiI_2 + Br_2 \)[/tex]) will not occur, indicated by 0.
Therefore, the expected results are:
[tex]\[ (1, 0) \][/tex]
### Reaction 1: [tex]\( Cl_2 + 2 RbI \rightarrow 2 RbCl + I_2 \)[/tex]
1. Identify Reactants and Products:
- Reactants: [tex]\( Cl_2 \)[/tex] and [tex]\( RbI \)[/tex]
- Products: [tex]\( RbCl \)[/tex] and [tex]\( I_2 \)[/tex]
2. Understand the Activity Series:
- Chlorine ([tex]\( Cl_2 \)[/tex]) and iodine ([tex]\( I_2 \)[/tex]) are both halogens, and they are in the activity series provided.
- The activity series tells us the relative reactivity of the halogens: [tex]\( F_2 > Cl_2 > Br_2 > I_2 \)[/tex].
3. Compare Reactivities (Activity Series):
- According to the activity series, chlorine ([tex]\( Cl_2 \)[/tex]) is more reactive than iodine ([tex]\( I_2 \)[/tex]).
4. Predict the Reaction:
- Since [tex]\( Cl_2 \)[/tex] is more reactive than [tex]\( I_2 \)[/tex], [tex]\( Cl_2 \)[/tex] will displace [tex]\( I \)[/tex] in [tex]\( RbI \)[/tex], forming [tex]\( RbCl \)[/tex] and releasing [tex]\( I_2 \)[/tex].
Conclusion for Reaction 1:
- The reaction [tex]\( Cl_2 + 2 RbI \rightarrow 2 RbCl + I_2 \)[/tex] will take place.
### Reaction 2: [tex]\( I_2 + NiBr_2 \rightarrow NiI_2 + Br_2 \)[/tex]
1. Identify Reactants and Products:
- Reactants: [tex]\( I_2 \)[/tex] and [tex]\( NiBr_2 \)[/tex]
- Products: [tex]\( NiI_2 \)[/tex] and [tex]\( Br_2 \)[/tex]
2. Understand the Activity Series:
- Iodine ([tex]\( I_2 \)[/tex]) and bromine ([tex]\( Br_2 \)[/tex]) are both halogens, and they are in the activity series provided.
- The activity series tells us the relative reactivity of the halogens: [tex]\( F_2 > Cl_2 > Br_2 > I_2 \)[/tex].
3. Compare Reactivities (Activity Series):
- According to the activity series, iodine ([tex]\( I_2 \)[/tex]) is less reactive than bromine ([tex]\( Br_2 \)[/tex]).
4. Predict the Reaction:
- Since [tex]\( I_2 \)[/tex] is less reactive than [tex]\( Br_2 \)[/tex], [tex]\( I_2 \)[/tex] cannot displace [tex]\( Br \)[/tex] in [tex]\( NiBr_2 \)[/tex], so the reaction will not proceed.
Conclusion for Reaction 2:
- The reaction [tex]\( I_2 + NiBr_2 \rightarrow NiI_2 + Br_2 \)[/tex] will not take place.
### Final Prediction:
Based on the analysis:
- Reaction 1 ([tex]\( Cl_2 + 2 RbI \rightarrow 2 RbCl + I_2 \)[/tex]) will occur, indicated by 1.
- Reaction 2 ([tex]\( I_2 + NiBr_2 \rightarrow NiI_2 + Br_2 \)[/tex]) will not occur, indicated by 0.
Therefore, the expected results are:
[tex]\[ (1, 0) \][/tex]
