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How many solutions are there to the following system of equations?

[tex]\[
\begin{array}{l}
y = 7x - 3 \\
-14x + 2y = -3
\end{array}
\][/tex]



Answer :

To determine how many solutions exist for the given system of equations:

1. [tex]\( y = 7x - 3 \)[/tex]
2. [tex]\(-14x + 2y = -3\)[/tex]

We will analyze the relationship between these two equations to see if they intersect at any point, which would represent a solution to the system.

Step 1: Rewrite the equations, if necessary, to easily compare them.

The first equation is already in slope-intercept form:
[tex]\[ y = 7x - 3 \][/tex]

The second equation is:
[tex]\[ -14x + 2y = -3 \][/tex]

Step 2: Substitute the expression for [tex]\( y \)[/tex] from the first equation into the second equation.

Substituting [tex]\( y = 7x - 3 \)[/tex] into [tex]\(-14x + 2y = -3\)[/tex]:

[tex]\[ -14x + 2(7x - 3) = -3 \][/tex]

Step 3: Simplify the substituted equation.

Distribute the 2 inside the parentheses:
[tex]\[ -14x + 14x - 6 = -3 \][/tex]

Combine the [tex]\( x \)[/tex] terms:
[tex]\[ 0x - 6 = -3 \][/tex]
[tex]\[ -6 = -3 \][/tex]

Step 4: Determine the validity of the resulting equation.

The equation [tex]\(-6 = -3\)[/tex] is a contradiction. This statement is not true and indicates that there is no value of [tex]\( x \)[/tex] that can satisfy both original equations simultaneously.

Conclusion:

Since the substitution resulted in a contradiction, there are no solutions to the system of equations. Therefore, the system of equations has:

0 solutions.

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