Which of the answer choices gives a correct grouping of the following quadratic?

[tex]\(6x^2 + 7x - 5\)[/tex]

Select the correct answer below:
A. [tex]\(6x^2 - 4x + 11x - 5\)[/tex]
B. [tex]\(6x^2 - 2x + 9x - 5\)[/tex]
C. [tex]\(6x^2 - 6x + 9x - 9\)[/tex]
D. [tex]\(6x^2 - 3x + 10x - 5\)[/tex]



Answer :

To determine the correct grouping that allows us to factor the quadratic expression [tex]\( 6x^2 + 7x - 5 \)[/tex], we need to find the correct pair of middle terms that sum to [tex]\( 7x \)[/tex] and whose product equals the product of the coefficient of [tex]\( x^2 \)[/tex] and the constant term. In this case, the coefficient of [tex]\( x^2 \)[/tex] is [tex]\( 6 \)[/tex], and the constant term is [tex]\(-5\)[/tex]. Therefore, the correct middle terms should come from pairs of terms that multiply to [tex]\( 6 \times (-5) = -30 \)[/tex] and sum to [tex]\( 7x \)[/tex].

Let's evaluate each option step-by-step:

### Option 1: [tex]\( 6x^2 - 4x + 11x - 5 \)[/tex]
- Sum of middle terms:
[tex]\[ -4x + 11x = 7x \][/tex]
- Product of middle terms:
[tex]\[ (-4) \times 11 = -44 \quad (\text{not equal to } -30) \][/tex]
This option does not work.

### Option 2: [tex]\( 6x^2 - 2x + 9x - 5 \)[/tex]
- Sum of middle terms:
[tex]\[ -2x + 9x = 7x \][/tex]
- Product of middle terms:
[tex]\[ (-2) \times 9 = -18 \quad (\text{not equal to } -30) \][/tex]
This option does not work.

### Option 3: [tex]\( 6x^2 - 6x + 9x - 9 \)[/tex]
- Sum of middle terms:
[tex]\[ -6x + 9x = 3x \quad (\text{not equal to } 7x) \][/tex]
This option does not work.

### Option 4: [tex]\( 6x^2 - 3x + 10x - 5 \)[/tex]
- Sum of middle terms:
[tex]\[ -3x + 10x = 7x \][/tex]
- Product of middle terms:
[tex]\[ (-3) \times 10 = -30 \quad (\text{equal to } -30) \][/tex]
This option works because both the sum and product conditions are satisfied.

Thus, the correct grouping of the quadratic [tex]\( 6x^2 + 7x - 5 \)[/tex] is given by:
[tex]\[ 6x^2 - 3x + 10x - 5 \][/tex]

The correct answer is:
[tex]\[ \boxed{6x^2 - 3x + 10x - 5} \][/tex]

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