If the weight of an object is greater than the buoyant force acting on it, it will sink.

What is the weight of a block of iron with the dimensions of 3.00 cm × 3.00 cm × 3.00 cm? The iron has a mass of 213 g.

Hint: Convert mass to weight using Weight = mg, where mass is in kilograms and gravity, g = 9.80 m/s².

Options:
A. 213 g
B. 209 N
C. 2.090 N
D. 0.213 kg



Answer :

To find the weight of a block of iron with the given dimensions and mass, we need to follow these steps:

1. Convert the mass from grams to kilograms:
The mass of the iron block is given as 213 grams. Since 1 kilogram equals 1000 grams, we convert the mass to kilograms by dividing by 1000:
[tex]\[ \text{mass in kg} = \frac{213 \text{ g}}{1000} = 0.213 \text{ kg} \][/tex]

2. Calculate the weight of the object:
Weight ([tex]\(W\)[/tex]) is calculated using the formula:
[tex]\[ W = mg \][/tex]
where [tex]\(m\)[/tex] is the mass in kilograms and [tex]\(g\)[/tex] is the acceleration due to gravity (9.80 m/s²).
Substituting the values:
[tex]\[ W = 0.213 \text{ kg} \times 9.80 \text{ m/s}^2 \][/tex]

3. Compute the result:
Now, multiply the mass by the acceleration due to gravity:
[tex]\[ W = 0.213 \text{ kg} \times 9.80 \text{ m/s}^2 = 2.0874 \text{ N} \][/tex]

Therefore, the weight of the block of iron is approximately 2.0874 Newtons. This value indicates the force due to gravity acting on the mass of the iron block in the Earth’s gravitational field.