Let's analyze the given problem and determine if the perimeter of the rectangle can be 60 units with the given length and width.
Given:
- Length [tex]\( L = 24 \)[/tex] units
- Width [tex]\( W = 11 \)[/tex] units
The formula for the perimeter [tex]\( P \)[/tex] of a rectangle is:
[tex]\[ P = 2L + 2W \][/tex]
Substitute the given length and width into the formula:
[tex]\[ P = 2(24) + 2(11) \][/tex]
Calculate the terms:
[tex]\[ P = 48 + 22 \][/tex]
[tex]\[ P = 70 \][/tex]
Therefore, the perimeter of the rectangle with length 24 units and width 11 units is:
[tex]\[ P = 70 \ \text{units} \][/tex]
Now we check the options:
1. No. If the length is 24 units and the width is 11 units, the perimeter would be [tex]\( P = 48 + 22 = 70 \)[/tex] units, not 60.
- This statement correctly calculates the perimeter as 70 units.
2. No. If the length is 24 units and the width is 11 units, the perimeter would be [tex]\( P = 24 + 22 = 66 \)[/tex] units, not 60.
- This statement incorrectly calculates the perimeter as 66 units, which is incorrect.
3. Yes. If the perimeter is 60 units and the width is 11 units, then [tex]\( P + W \)[/tex] is greater than 48.
- This statement is unrelated to the correct calculation of the perimeter.
4. Yes. If the length is 24 units and the width is 11 units, then [tex]\( P = 2L + 2W = 60 \)[/tex].
- This statement is incorrect because the correct perimeter is 70 units, not 60.
Therefore, the correct answer is:
No. If the length is 24 units and the width is 11 units, the perimeter would be [tex]\( P = 48 + 22 = 70 \)[/tex] units, not 60.
