Tick the correct answer for each of the following questions:

(a) [tex]\((4, -x)(3x + y x^4 + 2 + 3x^2)\)[/tex]

(b) [tex]\((x + 3)^7 - 5 = x^2 + 1\)[/tex]

(c) [tex]\((k - 4)x^2 - 3x - 9, k = 4\)[/tex]

(d) [tex]\((x + v^3 = x^3 - 5)\)[/tex]



Answer :

It appears there's a misunderstanding or a mix of problems in the provided data. However, I can address solving typical algebraic problems step-by-step. Below are interpretations of potential algebra problems that might match your request:

### Problem Interpretation and Solutions:

1. Solve the following equation for x:
[tex]\[ (4 - x)(3x + yx^4 + 2 + 3x^2) \][/tex]
This expression is not an equation (since it is not set to zero or any other value). Thus, there's no solution for x directly but rather a simplification or an evaluation given specific values of x and y.

2. Solve for x when [tex]\( k = 4 \)[/tex] in this equation:
[tex]\[(k - 4)x^2 - 3x - 9 = 0 \][/tex]
Since [tex]\(k = 4\)[/tex]:
[tex]\[ (4 - 4)x^2 - 3x - 9 = 0 \][/tex]
This simplifies to:
[tex]\[ 0 - 3x - 9 = 0 \quad \rightarrow \quad -3x - 9 = 0 \][/tex]
[tex]\[ -3x = 9 \quad \rightarrow \quad x = -3 \][/tex]

3. Solve the following equation:
[tex]\[ (x + 3)^7 - 5 = x^2 + 1 \][/tex]
This would typically require advanced methods or numerical approximations given the complexities of polynomial equations. However, verifying any simple integer or fractional value might be warranted, but here it doesn't indicate simple solvability from intuitive inspection without further context.

4. Solve the following equation:
[tex]\[ x + v^3 = x^3 - 5 \][/tex]
Here, [tex]\(v\)[/tex] is likely meant to be [tex]\(x\)[/tex], thus rendering:
[tex]\[ x + x^3 = x^3 - 5 \][/tex]
Simplify by subtracting [tex]\(x^3\)[/tex] from both sides:
[tex]\[ x = -5 \][/tex]

Given the provided scenarios and solutions, the main operation involves understanding and context evaluation since direct analytical solutions might be complex or undefined without additional context. Please correct or provide additional specifications if there is a mix-up.

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