What is [tex]\( y = -\frac{1}{3}x - 9 \)[/tex] written in standard form?

Choose 1 answer:
(A) [tex]\( \frac{1}{3}x + y + 9 = 0 \)[/tex]
(B) [tex]\( 3y = -x - 27 \)[/tex]
(C) [tex]\( y = -\frac{1}{3}(x + 27) \)[/tex]
(D) [tex]\( x + 3y = -27 \)[/tex]



Answer :

To convert the equation [tex]\( y = -\frac{1}{3}x - 9 \)[/tex] into standard form, we need to follow specific steps:

1. Start with the given equation in slope-intercept form:
[tex]\[ y = -\frac{1}{3}x - 9 \][/tex]

2. The standard form of a linear equation is [tex]\( Ax + By = C \)[/tex], where [tex]\( A \)[/tex], [tex]\( B \)[/tex], and [tex]\( C \)[/tex] are integers, and [tex]\( A \)[/tex] should be a non-negative integer.

3. To eliminate the fraction, multiply every term by 3 to clear the denominator:
[tex]\[ 3y = -x - 27 \][/tex]

4. Rearrange the equation to get all terms involving [tex]\( x \)[/tex] and [tex]\( y \)[/tex] on one side:
[tex]\[ x + 3y = -27 \][/tex]

This is now in the standard form [tex]\( Ax + By = C \)[/tex].

Thus, the correct answer is [tex]\( \boxed{D} \)[/tex].