To determine the force acting on a mass of [tex]\(10 \, \text{kg}\)[/tex] moving with a constant velocity of [tex]\(2 \, \text{m/s}\)[/tex], we can follow the steps below:
1. Understand the Problem:
- We have a mass, [tex]\(m = 10 \, \text{kg}\)[/tex].
- The object is moving with a constant velocity, [tex]\(v = 2 \, \text{m/s}\)[/tex].
2. Recall Newton's First Law:
- Newton's First Law states that an object will remain at rest or in uniform motion unless acted upon by a net external force.
3. Constant Velocity Implication:
- Since the object is moving with constant velocity, there is no acceleration. Acceleration ([tex]\(a\)[/tex]) is zero.
4. Newton's Second Law:
- Newton's Second Law of Motion states that the force ([tex]\(F\)[/tex]) acting on an object is the product of its mass ([tex]\(m\)[/tex]) and its acceleration ([tex]\(a\)[/tex]):
[tex]\[
F = m \cdot a
\][/tex]
5. Apply the Information:
- Given that acceleration [tex]\(a = 0\)[/tex]:
[tex]\[
F = 10 \, \text{kg} \times 0 \, \text{m/s}^2 = 0 \, \text{N}
\][/tex]
Therefore, the force acting on the mass of [tex]\(10 \, \text{kg}\)[/tex], moving with a constant velocity of [tex]\(2 \, \text{m/s}\)[/tex], is [tex]\(0 \, \text{N}\)[/tex].
So, the correct answer is:
d. zero
