The pressure inside of a 5.86 L cylinder is 6.27 atm at 368 K. Calculate the number of moles of gas in the
cylinder.
0.822 mol
1.22 mol
1110 mol
0.122 mol



Answer :

Answer:

1.22 mol

Explanation:

Pre-Solving

We are given that a 5.86 L cylinder has a pressure of 6.27 atm at 368 K. We want to know how many moles of gas are present at these conditions.

We can use the ideal gas law in order to solve this question; recall that the ideal gas law is PV = nRT, where P is pressure in atm, V is volume in L, n is amount in moles, R is a constant ([tex]0.0821 \frac{atmL}{molK}[/tex]), and T is temperature in K.

Solving

Since we are given all other variables in the correct units, we can substitute what we know into the equation:

[tex]5.86 L * 6.27 atm = n * 0.0821 \frac{atmL}{molK} * 368 K[/tex]

Divide both sides by [tex]0.0821 \frac{atmL}{molK} * 368 K[/tex]

[tex]n = \frac{5.86 L * 6.27 atm}{0.0821 \frac{atmL}{molK} * 368 K } = 1.22 mol[/tex] (rounded to three sig figs)

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