Let [tex]\( n \)[/tex] be a whole number, and consider the statements below.
[tex]\( p: n \)[/tex] is a multiple of two.
[tex]\( q: n \)[/tex] is an even number.

Which of the following is equivalent to [tex]\( \sim q \rightarrow \sim p \)[/tex]?

A. [tex]\( \sim q \rightarrow \sim p \)[/tex]
B. [tex]\( q \rightarrow p \)[/tex]
C. [tex]\( p \rightarrow q \)[/tex]
D. [tex]\( \sim p \rightarrow \sim q \)[/tex]



Answer :

Alright, let's break down the provided logical statements to find which one is equivalent to [tex]\(\sim q \rightarrow \sim p\)[/tex].

Given:
- [tex]\( p \)[/tex]: [tex]\( n \)[/tex] is a multiple of two.
- [tex]\( q \)[/tex]: [tex]\( n \)[/tex] is an even number.

We need to determine the statement equivalent to [tex]\(\sim q \rightarrow \sim p\)[/tex].

### Understanding the Given Statement:

1. [tex]\(\sim q\)[/tex]: [tex]\( n \)[/tex] is not an even number.
2. [tex]\(\sim p\)[/tex]: [tex]\( n \)[/tex] is not a multiple of two.

Thus, [tex]\(\sim q \rightarrow \sim p\)[/tex] is read as:
"If [tex]\( n \)[/tex] is not an even number, then [tex]\( n \)[/tex] is not a multiple of two."

### Finding the Equivalent Statement:

To find the equivalent statement, we can use the rule of contrapositive. The contrapositive of a statement "A implies B" is "not B implies not A", and both are logically equivalent.

Here's how we apply this:

- The statement we have is [tex]\(\sim q \rightarrow \sim p\)[/tex].
- The contrapositive of [tex]\(\sim q \rightarrow \sim p\)[/tex] is [tex]\( p \rightarrow q\)[/tex].

Here’s why [tex]\( p \rightarrow q\)[/tex] is equivalent:
- [tex]\( p\)[/tex]: [tex]\( n \)[/tex] is a multiple of two.
- [tex]\( q\)[/tex]: [tex]\( n \)[/tex] is an even number.

So, [tex]\( p \rightarrow q \)[/tex] means:
"If [tex]\( n \)[/tex] is a multiple of two, then [tex]\( n \)[/tex] is an even number."

### Conclusion:

After the analysis, we find that [tex]\( p \rightarrow q \)[/tex] is equivalent to [tex]\(\sim q \rightarrow \sim p\)[/tex].

Therefore, the correct option is:

[tex]\[ p \rightarrow q \][/tex]

So, the statement equivalent to [tex]\(\sim q \rightarrow \sim p\)[/tex] is [tex]\( p \rightarrow q \)[/tex]. The correct answer is:

[tex]\[ \text{3) } p \rightarrow q \][/tex]