A horse owner needs to replace four sections of a corral for the horses.

- The first section needs 26 yards of fencing.
- The second section needs [tex]\(10 \frac{3}{5}\)[/tex] yards.
- The third section needs [tex]\(10 \frac{1}{5}\)[/tex] yards.
- The fourth section needs [tex]\(8 \frac{3}{10}\)[/tex] yards.

How many yards are needed to repair all four sections of the fencing?



Answer :

Certainly! Let's go through the problem step by step to determine the total length of fencing needed for the four sections of the coral.

1. Identify the lengths of each section:
- The first section needs 26 yards of fencing.
- The second section needs [tex]\(10 \frac{3}{5}\)[/tex] yards.
- The third section needs [tex]\(10 \frac{1}{5}\)[/tex] yards.
- The fourth section needs [tex]\(8 \frac{3}{10}\)[/tex] yards.

2. Convert the mixed numbers to improper fractions or decimals for easier addition:
- [tex]\(10 \frac{3}{5}\)[/tex] can be converted to a decimal:
[tex]\[ 10 \frac{3}{5} = 10 + \frac{3}{5} = 10 + 0.6 = 10.6 \][/tex]
- [tex]\(10 \frac{1}{5}\)[/tex] can also be converted to a decimal:
[tex]\[ 10 \frac{1}{5} = 10 + \frac{1}{5} = 10 + 0.2 = 10.2 \][/tex]
- [tex]\(8 \frac{3}{10}\)[/tex] can be converted to a decimal:
[tex]\[ 8 \frac{3}{10} = 8 + \frac{3}{10} = 8 + 0.3 = 8.3 \][/tex]

3. Add the lengths together:
- First section: [tex]\( 26 \)[/tex] yards
- Second section: [tex]\( 10.6 \)[/tex] yards
- Third section: [tex]\( 10.2 \)[/tex] yards
- Fourth section: [tex]\( 8.3 \)[/tex] yards

Add these values together to find the total length of fencing needed:
[tex]\[ 26 + 10.6 + 10.2 + 8.3 \][/tex]

Let's add them step-by-step:
- First, add [tex]\(26\)[/tex] and [tex]\(10.6\)[/tex]:
[tex]\[ 26 + 10.6 = 36.6 \][/tex]
- Next, add [tex]\(36.6\)[/tex] and [tex]\(10.2\)[/tex]:
[tex]\[ 36.6 + 10.2 = 46.8 \][/tex]
- Finally, add [tex]\(46.8\)[/tex] and [tex]\(8.3\)[/tex]:
[tex]\[ 46.8 + 8.3 = 55.1 \][/tex]

So, the total length of fencing needed to repair the four sections is approximately 55.1 yards.