If the actual yield of sodium chloride from the reaction of sodium and chlorine is 6.4 g, and the theoretical yield is 7.42 g, what is the percent yield?

[tex]\[ 2 Na_{(s)} + Cl_{2(g)} \rightarrow 2 NaCl_{(s)} \][/tex]

A. 86%
B. 170%
C. 30%
D. 120%



Answer :

To find the percent yield of sodium chloride (NaCl) from the given reaction, we need to use the actual yield and the theoretical yield provided in the problem. Here's a step-by-step solution:

1. Identify the actual yield and theoretical yield:
- Actual yield: [tex]\(6.4 \, \text{g}\)[/tex]
- Theoretical yield: [tex]\(7.42 \, \text{g}\)[/tex]

2. Understand the formula for percent yield:
The percent yield is calculated using the following formula:
[tex]\[ \text{Percent yield} = \left( \frac{\text{Actual yield}}{\text{Theoretical yield}} \right) \times 100 \][/tex]

3. Substitute the given values into the formula:
- Actual yield = [tex]\(6.4 \, \text{g}\)[/tex]
- Theoretical yield = [tex]\(7.42 \, \text{g}\)[/tex]

[tex]\[ \text{Percent yield} = \left( \frac{6.4}{7.42} \right) \times 100 \][/tex]

4. Calculate the fraction:
[tex]\[ \frac{6.4}{7.42} \approx 0.8625336927223721 \][/tex]

5. Multiply by 100 to get the percent yield:
[tex]\[ 0.8625336927223721 \times 100 \approx 86.25336927223721 \][/tex]

6. Round to a reasonable number of significant figures:
[tex]\[ \text{Percent yield} \approx 86\% \][/tex]

Hence, the percent yield of sodium chloride is approximately 86%. Therefore, the correct answer is:

[tex]\[ \boxed{86 \%} \][/tex]