To determine the magnitude of a marble’s momentum, we should use the classical equation for momentum, which is given by:
[tex]\[ \text{momentum} = \text{mass} \times \text{velocity} \][/tex]
Here, we have the following values provided:
- Mass (m) of the marble: [tex]\( 1.5 \)[/tex] grams
- Velocity (v) of the marble: [tex]\( 0.50 \)[/tex] cm/s
We plug these values into our momentum formula:
[tex]\[ \text{momentum} = 1.5 \, \text{grams} \times 0.50 \, \text{cm/s} \][/tex]
[tex]\[ \text{momentum} = 0.75 \, \left( \frac{\text{grams} \cdot \text{cm}}{\text{s}} \right) \][/tex]
Thus, the magnitude of the marble's momentum is:
[tex]\[ 0.75 \, \frac{\text{grams} \cdot \text{cm}}{\text{s}} \][/tex]
Therefore, the correct answer is:
[tex]\[ 0.75 \, \frac{g \cdot cm}{s} \][/tex]
