Select the correct answer.

An engineer is designing an arch-shaped gate for the entrance to an amusement park. The gate must be 80 feet wide and 25 feet tall. What will be the equation of the parabolic shape of the gate?

A. [tex]\( x^2 = -16(y-25) \)[/tex]
B. [tex]\( (x-16)^2 = -4(y-25) \)[/tex]
C. [tex]\( x^2 = -64(y-25) \)[/tex]
D. [tex]\( (x-25)^2 = -16(y-16) \)[/tex]
E. [tex]\( x^2 = -40(y-25) \)[/tex]



Answer :

To find the equation of the parabolic shape of the gate, we need to follow these steps:

1. Define the coordinate system and the parabola form:
The arch is symmetric about the y-axis since it's the shape of a gate. Therefore, we can place the vertex of the parabola at the highest point of the arch, which is at [tex]\((0, 25)\)[/tex]. Given this, the standard form of the equation of the parabola that opens downwards is:
[tex]\[ x^2 = -a(y - 25) \][/tex]
where [tex]\((h, k) = (0, 25)\)[/tex] and [tex]\(-a\)[/tex] is a coefficient to be determined.

2. Determine the width of the arch:
The arch is 80 feet wide, so half the width is 40 feet. Therefore, the points where the parabola intersects the x-axis are [tex]\((40, 0)\)[/tex] and [tex]\((-40, 0)\)[/tex].

3. Substitute a point on the parabola to find the value of [tex]\(a\)[/tex]:
Substitute the point [tex]\((40, 0)\)[/tex] into the parabola equation [tex]\(x^2 = -a(y - 25)\)[/tex]:

[tex]\[ 40^2 = -a(0 - 25) \][/tex]
Simplify this equation:
[tex]\[ 1600 = 25a \][/tex]
Solving for [tex]\(a\)[/tex]:
[tex]\[ a = \frac{1600}{25} = 64 \][/tex]

4. Write the final equation:
Substitute [tex]\(a = 64\)[/tex] back into the parabola equation:
[tex]\[ x^2 = -64(y - 25) \][/tex]

Hence, the correct answer is:
[tex]\[ \boxed{x^2 = -64(y - 25)} \][/tex]

So, the correct answer is:

C. [tex]\(x^2 = -64(y - 25)\)[/tex]

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