Solve the system using substitution:

[tex]\[ \begin{array}{l}
5x - 2y = 49 \\
-6x + y = -49
\end{array} \][/tex]

- One solution: [tex]\(\square\)[/tex]
- No solution
- Infinite number of solutions



Answer :

To solve the system of linear equations using the substitution method, follow these steps:

Given the system:
[tex]\[ \begin{array}{l} 5x - 2y = 49 \quad \text{(Equation 1)} \\ -6x + y = -49 \quad \text{(Equation 2)} \end{array} \][/tex]

1. Solve Equation 2 for [tex]\(y\)[/tex]:
[tex]\[ -6x + y = -49 \][/tex]
[tex]\[ y = 6x - 49 \][/tex]

2. Substitute [tex]\(y\)[/tex] in Equation 1:
Replace [tex]\(y\)[/tex] in Equation 1 with the expression obtained from Equation 2:
[tex]\[ 5x - 2(6x - 49) = 49 \][/tex]
Simplify the expression inside the parentheses:
[tex]\[ 5x - 12x + 98 = 49 \][/tex]
Combine like terms:
[tex]\[ -7x + 98 = 49 \][/tex]
Isolate [tex]\(x\)[/tex] by first subtracting 98 from both sides:
[tex]\[ -7x = 49 - 98 \][/tex]
[tex]\[ -7x = -49 \][/tex]
Divide both sides by -7:
[tex]\[ x = 7 \][/tex]

3. Substitute [tex]\(x = 7\)[/tex] back into the expression for [tex]\(y\)[/tex]:
Use the value of [tex]\(x\)[/tex] in the equation [tex]\( y = 6x - 49 \)[/tex]:
[tex]\[ y = 6(7) - 49 \][/tex]
Simplify the right-hand side:
[tex]\[ y = 42 - 49 \][/tex]
[tex]\[ y = -7 \][/tex]

So, the solution to the system of equations is:
[tex]\[ (x, y) = (7, -7) \][/tex]

Therefore, the system has one solution:
[tex]\[ \boxed{(7, -7)} \][/tex]

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