Answer :
To determine the extremes of the proportion [tex]\(\frac{3}{4} = \frac{6}{8}\)[/tex], we need to identify the first and last terms in the given proportion.
1. The proportion is written as a fraction on both sides of the equals sign. The first term is the numerator of the first fraction, and the last term is the denominator of the second fraction.
2. In the proportion [tex]\(\frac{3}{4}\)[/tex], the first term (numerator) is [tex]\(3\)[/tex].
3. In the proportion [tex]\(\frac{6}{8}\)[/tex], the last term (denominator) is [tex]\(8\)[/tex].
4. Therefore, the extremes of the proportion [tex]\(\frac{3}{4} = \frac{6}{8}\)[/tex] are [tex]\(3\)[/tex] and [tex]\(8\)[/tex].
So, the correct answer is B. 3 and 8.
1. The proportion is written as a fraction on both sides of the equals sign. The first term is the numerator of the first fraction, and the last term is the denominator of the second fraction.
2. In the proportion [tex]\(\frac{3}{4}\)[/tex], the first term (numerator) is [tex]\(3\)[/tex].
3. In the proportion [tex]\(\frac{6}{8}\)[/tex], the last term (denominator) is [tex]\(8\)[/tex].
4. Therefore, the extremes of the proportion [tex]\(\frac{3}{4} = \frac{6}{8}\)[/tex] are [tex]\(3\)[/tex] and [tex]\(8\)[/tex].
So, the correct answer is B. 3 and 8.
