We can describe [tex]\(12x - 8\)[/tex] as an expression.
It can also be written as [tex]\(4(3x - 2)\)[/tex].

4 and [tex]\(3x - 2\)[/tex] are both [tex]\(\square\)[/tex] of [tex]\(12x - 8\)[/tex].



Answer :

Certainly! Let's go through the process of rewriting the given expression step by step.

1. Given Expression:
The original expression provided is [tex]\( 12x - 8 \)[/tex].

2. Factorization:
We need to factorize the expression [tex]\( 12x - 8 \)[/tex]. Let's identify the common factor in both terms:
- The terms are [tex]\( 12x \)[/tex] and [tex]\( -8 \)[/tex].
- The greatest common divisor (GCD) of 12 and 8 is 4, since 4 is the largest number that can divide both 12 and 8 without leaving a remainder.

3. Rewriting the Expression:
We can divide both terms by this common factor 4:
[tex]\[ 12x \div 4 = 3x \][/tex]
[tex]\[ -8 \div 4 = -2 \][/tex]
By factoring out the common factor 4 from each term, we rewrite the expression as:
[tex]\[ 12x - 8 = 4(3x - 2) \][/tex]

4. Factors of the Expression:
When we factor [tex]\( 12x - 8 \)[/tex] into [tex]\( 4(3x - 2) \)[/tex], the elements we have factored out are:
[tex]\[ 4 \quad \text{and} \quad (3x - 2) \][/tex]
Hence, 4 and [tex]\( 3x - 2 \)[/tex] are both factors of [tex]\( 12x - 8 \)[/tex].

Thus, in the context of the equation, the factors of [tex]\( 12x - 8 \)[/tex] are [tex]\( 4 \)[/tex] and [tex]\( 3x - 2 \)[/tex].